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Q.

The ionization energy of hydrogen is 13.6 eV and the first ionization energy of helium is 24.6 eV. Energy evolved in the following electron-gain process He2+​​+​2e−  →​​He

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answer is 79.

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Detailed Solution

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H  →H+       13.6 eV

He  →He+       24.6 eV

Thus the energy for the ionosation of  He2+ to He+

4 x 13.6 = 54.4 eV

Energy given out  He2++2e−  → He

24.6 + 54.4 =79

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