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Q.

The ionization potential of hydrogen atom is 13.6 V. How much energy need to be supplied to ionize the hydrogen atom in the first excited state.

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a

13.6 eV

b

27.2 eV

c

3.4 eV

d

6.8 eV

answer is C.

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Detailed Solution

Energy of the n^th cell = $\frac{1}{n^{2}} \times 13.6 e V$

Energy in the 1^st excited state is n = 2

Then $\frac{1}{2^{2}} \times 13.6 e V = 3.4 e V$

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The ionization potential of hydrogen atom is 13.6 V. How much energy need to be supplied to ionize the hydrogen atom in the first excited state.