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Q.

The isotope 92U238  decays successively to form 90Th234,  91Pa234 , 92U234 ,90Th230 and 88Ra226 . What are the radiations emitted in these five steps?

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a

α,α,α,β,β

b

α,β,β,α,β

c

α,β,α,α,α

d

α,β,β,α,α

answer is D.

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Detailed Solution

 92U238→α90Th234→β 91Pa234→β92U234→α 90Th230→α88Ra226→β
∴Five steps are →α,β,β,α,α

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