The isotope 92U238 decays successively to form 90Th234, 91Pa234 , 92U234 ,90Th230 and 88Ra226 . What are the radiations emitted in these five steps?

92U238→α90Th234→β 91Pa234→β92U234→α 90Th230→α88Ra226→β∴Five steps are →α,β,β,α,α

The isotope 92U238 decays successively to form 90Th234, 91Pa234 , 92U234 ,90Th230 and 88Ra226 . What are the radiations emitted in these five steps?

92U238→α90Th234→β 91Pa234→β92U234→α 90Th230→α88Ra226→β∴Five steps are →α,β,β,α,α

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The isotope ₉₂U²³⁸ decays successively to form ₉₀Th²³⁴, ₉₁Pa²³⁴ , ₉₂U²³⁴ ,₉₀Th²³⁰ and ₈₈Ra²²⁶ . What are the radiations emitted in these five steps?

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$α, α, α, β, β$

$α, β, β, α, β$

$α, β, α, α, α$

$α, β, β, α, α$

answer is D.

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Detailed Solution

$\begin{array}{l} _{92} U^{238} {\overset{α}{\to}}_{90} {Th}^{234} \overset{β}{\to} \\ _{91} {Pa}^{234} {\overset{β}{\to}}_{92} U^{234} \overset{α}{\to} \\ _{90} {Th}^{230} {\overset{α}{\to}}_{88} {Ra}^{226} \overset{β}{\to} \end{array}$
$∴$ Five steps are $\to α, β, β, α, α$