The isotope ${}^{14}\mathrm{C}$undergoes radioactive decay slowly. Which mode of decay is most likely?

C degrades through a process known as beta decay. One of the neutrons in the carbon atom turns into a proton during this process, which results in the decay of a ${}^{14}\mathrm{C}$ atom into a ${}^{14}\mathrm{N}$ atom. By adding one more proton to the atom, this results in the formation of a nitrogen atom rather than a carbon atom.