The IUPAC name for the following compounds

 

The structure in the image contains both an aldehyde (-CHO) and a carboxylic acid (-COOH) functional group, as well as a methyl group and a double bond. Let’s assign IUPAC nomenclature step by step:

Stepwise Solution

1. Identify the longest carbon chain containing both functional groups:
   • The chain contains 6 carbon atoms.
2. Assign priority to functional groups:
   • Carboxylic acid gets highest priority, so numbering starts from the -COOH group.
3. Number the chain:
   • 1: -COOH
   • 2: C with -CH₃ (methyl)
   • 3: double bond location (3-4)
   • 5: -CHO (aldehyde)
4. Substituents:
   • Methyl at position 2.
   • Aldehyde (oxo group) at position 5.
   • Double bond between positions 3 and 4.
5. Final name format:
   • 5-Formyl-2-methylhex-3-enoic acid (where formyl is the prefix for the –CHO when a higher-priority group is present)

IUPAC Name

The IUPAC name for the compound in the image is: 5-Formyl-2-methylhex-3-enoic acid.

If you need this explanation in HTML, let me know.The given structure is a six-carbon chain with a carboxylic acid (-COOH) at one end, an aldehyde (-CHO) group at the fifth carbon, a double bond between carbons 3 and 4, and a methyl group at carbon 2.

Stepwise Solution

• Longest chain: 6 carbons (hexanoic acid backbone)
• Principal group: Carboxylic acid (so, numbering starts from the –COOH end)
• Substituents:
  • Methyl group at carbon-2
  • Aldehyde (as a formyl/oxo substituent) at carbon-5
  • Double bond between C-3 and C-4

IUPAC Name

The IUPAC name is 5-formyl-2-methylhex-3-enoic acid.