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The IUPAC name of an unsymmetrical ether with the molecular formula $C_{4} H_{10} O$

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$Ethoxy ethane$

$Ethoxy propane$

$Methoxy ethane$

$Methoxy propane$

answer is D.

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Detailed Solution

$C_{4} H_{10} O$ a potential structure for ether is, ${CH}_{3} {CH}_{2} {CH}_{2} - {OCH}_{3}$ . Methoxy propane is its IUPAC name.

Hence, the correct option is an option (D) Methoxy propane.

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