The IUPAC name of the compound $\mathrm{Br}\left(\mathrm{Cl}\right)\mathrm{CH}.{\mathrm{CF}}_3$ is

Answer: 1,1,1-trifluoro-2-bromo-2-chloropropane.

The IUPAC name explained

The compound shown has a central carbon bonded to four groups: Br, Cl, CH₃, and CF₃. This makes a three-carbon chain overall: CH3–C(Br)(Cl)–CF3. The longest carbon chain contains three carbons, so the parent hydrocarbon is propane. Both halogens (bromo and chloro) sit on the middle carbon (carbon-2). The terminal carbon on one end is a trifluoromethyl group, which in IUPAC is named as the parent substituent “1,1,1-trifluoro” on carbon-1 of propane. Putting all parts together in correct order and with lowest locants gives 1,1,1-trifluoro-2-bromo-2-chloropropane.

How to name it step by step (IUPAC rules)

1. Select the parent chain: Longest continuous chain is three carbons → propane.
2. Number the chain: Start from the end nearest the first point of difference. The CF₃ end gives the lowest set of locants for all substituents.
3. Identify and locate substituents:
   • Three fluorines on carbon-1 → 1,1,1-trifluoro.
   • Bromine on carbon-2 → 2-bromo.
   • Chlorine on carbon-2 → 2-chloro.
4. Assemble the name: List substituents alphabetically then parent: 1,1,1-trifluoro-2-bromo-2-chloropropane.