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The junction diode in the following circuit requires a minimum current of 1 mA to be above the knee point (0.7 V) of its I-V characteristic curve. The voltage across the diode is independent of current above the knee point .lf V_B =5 V then the maximum value of R so that the voltage is above the knee point, will be

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$4.3 k Ω$

$860 k Ω$

$4.3 Ω$

$860 Ω$

answer is A.

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Detailed Solution

At knee point, voltage across the diode is 0.7 V.
Hence voltage across resistance R is 5 - 0.7 = 4.3 V.

$U \sin g V = i R \Rightarrow 4.3 = 1 \times 10^{- 3} \times R \Rightarrow R = 4.3 k Ω$

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