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The $k_{α}$ wavelength of an element with atomic number z is $λ_{z}$ . The $k_{α}$ wavelength of an element with atomic number 2z is $λ_{z}$ . How are $λ_{z}$ and $λ_{2 z}$ related?

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$λ_{z} > 4 λ_{2 z}$

$λ_{2} < 4 λ_{2 z}$

$λ_{2} = 4 λ_{2 z}$

Depending on z, $λ_{z}$ could be greater than or less than $4 λ_{2 z}$

answer is A.

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Detailed Solution

$\frac{h C}{λ_{k_{α}}} = (3.6) {(z - 1)}^{2} (\frac{1}{1^{2}} - \frac{1}{2^{2}})$

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