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$The \frac{K_{c}}{K_{P}} ratio will be highest in case of$ _____?

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$2 {SO}_{3_{(g)}} ⇌ 2 {SO}_{2_{(g)}} + O_{2_{(g)}}$

$3 {Fe}_{(s)} + 4 H_{2} O_{(g)} ⇌ {Fe}_{3} O_{4 (s)} + 4 H_{2_{(g)}}$

$7 H_{2_{(g)}} + 2 N O_{2_{(g)}} ⇌ 2 N H_{3_{(g)}} + 4 H_{2} O_{(g)}$

${NH}_{2} COONH 4_{(s)} ⇌ 2 {NH}_{3_{(g)}} + {CO}_{2_{(g)}}$

answer is C.

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Detailed Solution

$\begin{array}{l} K_{P} = K_{C} (R T)^{Δ n} \\ \frac{K_{C}}{K_{P}} = (R T)^{- Δ n} \end{array}$

Among the given options $' Δ n^{'}$ value is more negative in option ‘C’, So it has highest ratio.

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