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The key for a door is in the bunch of 10 keys. A man attempts to open the door by trying keys at random discarding the wrong key. The probability that the door is opened in the 5^th trial is

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0.6

0.1

0.2

0.5

answer is A.

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Detailed Solution

Req. probability $= \frac{9}{10} \frac{8}{9} \frac{7}{8} \frac{6}{7} \frac{1}{6}$
$\begin{array}{l} = \frac{1}{10} \\ = 0.1 \end{array}$

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