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Q.

The kinetic data for the reaction OCl+IOHOI+Cl at 298 is as follows:

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The rate low for the formation of OI is

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a

r=kOCl2

b

r=kOClI/OH

c

r=kOClI

d

r=kI2OCl

answer is D.

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Detailed Solution

On doubling the OCl keeping the Iand OH constant, the rate of formation of OH is doubled, hence the order of reaction with respect to OCl is one. On doubling the I keeping the OCl and OH constant, the rate of formation of OI is doubled, hence the order of reaction with respect to 1- is one. On changing the OH to a half-value, the rate of formation of OI is doubled. Hence, the order of reaction with respect to OH is -1.

Hence the rate law is r=kOClIOH1=kOClI/OH

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