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The kinetic energies of a planet in an elliptical orbit about the Sun, at positions A, B and C are $K_{A}, K_{B} a n d K_{C}$
respectively. AC is the major axis and SB is perpendicular to AC to the position of the Sun S as shown in the figure. Then

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$K_{A} > K_{B} > K_{C}$

$K_{A} < K_{B} < K_{C}$

$K_{B} < K_{A} < K_{C}$

$K_{B} > K_{A} > K_{C}$

answer is B.

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Detailed Solution

$L = m v r = I ω = constant$

$KE = \frac{1}{2} {mv}^{2}$

$v \propto 1 / r$

$r_{A} < r_{B} < r_{C} K E_{A} > K E_{B} > K E_{C}$

$\Rightarrow V_{A} > V_{B} > V_{C}$

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