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The kinetic energy (inJ) of a particle of mass 4.5×10^–31 kg having a wavelength of 1000nm is (h = 6.62 × 10^–34 Js)

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4.86×10^–24

2.43×10^–26

2.43×10^–24

4.86×10^–25

answer is D.

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Detailed Solution

$λ = \frac{h}{\sqrt{2 . K E . m}} 1000 \times 10^{- 9} = \frac{6.626 \times 10^{- 34}}{\sqrt{2 \times K E \times 4.5 \times 10^{- 31}}} K E = 4.86 \times 10^{- 25} J$

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