The kinetic energy of 8 grams of hydrogen at 27°C  when compared to that of 8 grams of oxygen at the same temperature is...... times

Amount of hydrogen gas ,m = 8 g

Molar mass of hydrogen gas, MW = 2g/mol

Number of moles of hydrogen gas is

${\mathrm{n}}_{{\mathrm{H}}_2}=\frac{\mathrm{mass} \mathrm{of} {\mathrm{H}}_2}{\mathrm{MW} \mathrm{of} {\mathrm{H}}_2}$

$\frac{8\mathrm{g}}{2 \mathrm{g}/\mathrm{mol}}=4 mol$

Amount of oxygen gas ,m = 8 g

Molar mass of oxygen gas, MW = 32g/mol

Number of moles of oxygen gas is

${\mathrm{n}}_{{\mathrm{H}}_2}=\frac{\mathrm{mass} \mathrm{of} {\mathrm{O}}_2}{\mathrm{MW} \mathrm{of} {\mathrm{O}}_2}$

$=\frac{8\mathrm{g}}{32/\mathrm{mol}}=\frac{1}{4}\mathrm{mol}$

$\frac{\mathrm{K}.\mathrm{E} {\mathrm{H}}_2}{\mathrm{K}.\mathrm{E} {\mathrm{O}}_2}=\frac{\frac{3}{2}{n}_{1}RT}{\frac{3}{2}{n}_{2}RT}$

$\frac{{\mathrm{n}}_1}{{\mathrm{n}}_2}=\frac{4}{\left(\frac{1}{4}\right)}$

=16

Therefore,$\frac{\mathrm{K}.\mathrm{E} {\mathrm{H}}_2}{\mathrm{K}.\mathrm{E} {\mathrm{O}}_2}=16$