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Q.

The kinetic energy of a body decreases by 19%. What is the percentage decrease in its linear momentum?

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answer is 10.

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Detailed Solution

As we know $K = \frac{p^{2}}{2 m}$

$\frac{k_{2}}{k_{1}} = \frac{p_{2}^{2}}{p_{1}^{2}} = \frac{81}{100}$

$\Rightarrow \frac{p_{2}}{p_{1}} = \frac{9}{10}$

So the momentum is decreased by 10%.

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