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The kinetic energy of a body is ‘E’. If one-fourth of its mass is removed and velocity is doubled, the new kinetic energy will be _____

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9E/4

answer is B.

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Detailed Solution

K.E = 1/2 x m x v² = E (given)

New kinetic energy (K’) = 1/2 x m’ x v’²

m’ = 3m/4; [one-fourth of mass is removed]

v’ = 2v; [velocity is doubled]

K.E’ = 1/2 x (3m/4) x (2v)²

= 3(1/2 x m x v²)

= 3 x E

= 3E.

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