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The kinetic energy of a body is increased by 300%. The momentum of the body would increase by:

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50%

100%

150%

300%

answer is B.

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Detailed Solution

KE = $\frac{P^{2}}{2 m}$ or $P^{2} \propto K E$ ----(i)

$K E_{2} = K E_{1} +$ $(\frac{300}{100}) K E_{1} = 4 K E_{1}$

From (i) $\frac{P_{2}}{P_{1}} =$ $\sqrt{\frac{K E_{2}}{K E_{1}}}$ = $\sqrt{\frac{4 K E_{1}}{1 K E_{1}}}$ = 2

It means momentum becomes twice, hence increase in momentum is 100%

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