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Q.

The kinetic energy of a body is 'K'. If one-fourth of its mass is removed and velocity is doubled, its new kinetic energy is,

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a

3 K

b

4 K

c

K

d

9K/4

answer is B.

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Detailed Solution

$K = \frac{1}{2} m v^{2}$

$K^{'} = \frac{1}{2} (\frac{3}{4} m) {(2 v)}^{2}$ = $3 K$

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The kinetic energy of a body is 'K'. If one-fourth of its mass is removed and velocity is doubled, its new kinetic energy is,