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Q.

The kinetic energy of a charged particle decreases by 10J as it moves from a point at a  potential 100 V to a point at potential 200 V. Then the charge on particle is

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a

0.1 C

b

1 C

c

0.01 C

d

10−3C

answer is B.

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Detailed Solution

ΔKE=w=qvv=v2−v1

10J=q200−100

q=0.1C

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