The kinetic energy of an electron emitted from a surface of a metal by light of wavelength 5.5 × 10−8cm(Threshold frequency for the metal is 3.62 × 1012s−1), is

v = cλ = 3 × 1010cms-15.5 × 10-8 cm = 5.5 × 1017s-1Further, 12 mu2 = h (v − v0)= 6.6 × 10-27 (5.5 × 1017s-1 − 3.62 × 1012s-1)

The kinetic energy of an electron emitted from a surface of a metal by light of wavelength 5.5 × 10−8cm(Threshold frequency for the metal is 3.62 × 1012s−1), is

v = cλ = 3 × 1010cms-15.5 × 10-8 cm = 5.5 × 1017s-1Further, 12 mu2 = h (v − v0)= 6.6 × 10-27 (5.5 × 1017s-1 − 3.62 × 1012s-1)

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The kinetic energy of an electron emitted from a surface of a metal by light of wavelength
$5.5 \times 10^{- 8} c m$ (Threshold frequency for the metal is $3.62 \times 10^{12} s^{- 1}$ ), is

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${6.6 × 10}^{-27} erg (- {5.5 × 10}^{17} s^{-1} {+ 3.62 × 10}^{12} s^{-1})$

${6.6 × 10}^{-27} erg ({5.5 × 10}^{17} s^{-1} - {3.62 × 10}^{12} s^{-1})$

${6.6 × 10}^{-27} erg ({5.5 × 10}^{17} s^{-1} {+ 3.62 × 10}^{12} s^{-1})$

${6.6 × 10}^{-27} erg (- {5.5 × 10}^{17} s^{-1} - {3.62 × 10}^{12} s^{-1})$

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Detailed Solution

$v = \frac{c}{λ} = \frac{{3 × 10}^{10} {cms}^{-1}}{{5.5 × 10}^{-8} cm} {= 5.5 × 10}^{17} s^{-1}$

$Further, \frac{1}{2} {mu}^{2} = h (v - v_{0})$

${= 6.6 × 10}^{-27} ({5.5 × 10}^{17} s^{-1} - {3.62 × 10}^{12} s^{-1})$

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The kinetic energy of an electron emitted from a surface of a metal by light of wavelength 5.5 × 10−8cm(Threshold frequency for the metal is 3.62 × 1012s−1), is

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The kinetic energy of an electron emitted from a surface of a metal by light of wavelength
$5.5 \times 10^{- 8} c m$ (Threshold frequency for the metal is $3.62 \times 10^{12} s^{- 1}$ ), is