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The kinetic energy of N molecules of $O_{2}$ is x joule at $- 123 ° C$ . Another sample of $O_{2}$ at 27° C has a kinetic energy of 2x. The latter sample contains ....molecules of $O_{2}$ .

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$\frac{N}{2}$

answer is A.

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Detailed Solution

$\begin{array}{l} x = \frac{3}{2} K \times N \times 150 \\ 2 x = \frac{3}{2} K \times N^{'} \times 300 \end{array}$

Dividing the two we get, N' = N

$5. \frac{3}{2} K T = K E_{avg}$

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