The Ksp of Ca(OH)2 is 4.42 x 10-5 at 25° C. A 500 mL of saturated solution of Ca(OH)2 is mixed with an equal volume of 0.4 M NaOH. How much Ca(OH)2 in mg is precipitated?

Solubility of Ca(OH)2 in saturated solution=4.42×10−543=0.0223 Mx(0.2+2x)2=4.42×10−5⇒x≃1.105×10−3 M.Ca(OH)2 pptd. =0.0223×0.5−1.105×10−3×1×74×1000 mg=743 mg

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The K_sp of Ca(OH)₂ is 4.42 x 10^-5 at 25° C. A 500 mL of saturated solution of Ca(OH)₂ is mixed with an equal volume of 0.4 M NaOH. How much Ca(OH)₂ in mg is precipitated?

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answer is 743.

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Detailed Solution

Solubility of Ca(OH)₂ in saturated solution

$= \sqrt[3]{\frac{4.42 \times 10^{- 5}}{4}} = 0.0223 M$

$\begin{array}{l} x (0.2 + 2 x)^{2} = 4.42 \times 10^{- 5} \\ \Rightarrow x ≃ 1.105 \times 10^{- 3} M . \end{array}$

$\begin{array}{l} Ca (OH)_{2} pptd. = [0.0223 \times 0.5 - 1.105 \times 10^{- 3} \times 1] \times 74 \times 1000 mg \\ = 743 mg \end{array}$

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