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The lamp of flash light is 1 .5 $Ω$ . It uses 3 cells each of 1 . 5 V and internal resistance 0 . 25 $Ω$ . What is the net potential difference across the lamp ?

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3 V

1.5 V

4.5 V

2.25 V

answer is C.

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Detailed Solution

$3 E = (1 \cdot 5 + 3 r) i$
or $3 \times 1 \cdot 5 = (1 \cdot 5 + 0 \cdot 75) i$
i = 2amp
$∴$ Potential difference = 2 x 1.5= 3 V

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