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The largest distance between the interatomic planes of a crystal is 2 x $10^{- 7}$ cm. The upper limit for the wavelength of X-rays which can be usefully studied with this crystal is

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20 Å

1 Å

2 Å

40 Å

answer is C.

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Detailed Solution

Bragg's law, $2 dsinθ = nλ or λ = \frac{2 dsinθ}{n}$
For maximum wavelength, $n_{\min} = 1, {(sinθ)}_{\max} = 1$

$∴ λ_{\max} = 2 d or λ_{\max} = 4 \times 10^{- 7} cm = 40 Å$

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