The last element of the p-block in 6th period is represented by the outermost electronic configuration.

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$4 f^{14} 5 d^{10} 6 s^{2} 6 p^{6}$

$\begin{aligned} 5 f^{14} 6 d^{10} 7 s^{2} 7 p^{0} \end{aligned}$

$4 f^{14} 5 d^{10} 6 s^{2} 6 p^{4}$

$\begin{aligned} 7 s^{2} 7 p^{6} \end{aligned}$

answer is C.

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Detailed Solution

The last element of p-Block in $6^{th}$ period is $R n - 86$ .

It's outer electronic configuration is $4 f^{14} 5 d^{10} 6 s^{2} 6 p^{6}$ .

It is a Noble Gas. Thus, the option C is correct.

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