The last three whole numbers before 7510001 are 7510000 ____,[[2]].

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Detailed Solution

The last three whole numbers before 7510001 are 7510000, 7509999, 7509998.
We know that in the number line the whole numbers start from zero and continues infinitely with the difference between any two consecutive ones as 1.
We start with the given number and subtract 1 from it.
7510001-1= 7510000.
In the next step, we again subtract 1 from the number obtained above.
7510000-1= 7509999
Finally, we again subtract 1 from the number obtained above.
7509999-1=7509998
The required three whole numbers before 7510001 are 7510000, 7509999, 7509998

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