The lateral surface area of a hollow cylinder is 4224 $c{m}^2$ . It is cut along its height and formed a rectangular sheet of width 33 cm. Find the perimeter of rectangular sheet?

Lateral surface area of hollow cylinder = 4224 $c{m}^2$ 

Width of rectangular sheet = 33 cm 

Let l be the length of the rectangular sheet 

Lateral surface area of cylinder = Area of rectangular sheet

$4224 =$ $l \times b$

$4224 = 33 \times l$ 

$l = \frac{4224}{33} = 128 cm$

Length of the rectangular sheet = 128 cm.

Perimeter of the sheet $= 2(l + b) = 2(128 + 33) = 2 \times 161 = 322 cm$

Hence, the required perimeter = 322 cm.