The lattice energy of NaCl is -780 kJ mol^-1 .The enthalpies of hydration of (g ) ${Na}_{(g)}^{+}_{}$ and ${Cl}_{(g)}^{-}$ are -406 kJ mol^- and -364 kJ mol^-1 .The enthalpy of solution of NaCl(s) is

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$738 KJ {mol}^{- 1}$

$10 kJ {mol}^{- 1}$

- $10 kJ {mol}^{- 1}$

$- 822 kJ {mol}^{- 1}$

answer is B.

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Detailed Solution

$\begin{array}{l} NaCl (s) \to {Na}^{+} (g) + {CL}^{-} (g) ΔH = + 780 kJ \\ {Na}^{+} (g) + aq \to {Na}^{+} (aq) ΔH = - 406 kJ \\ {Cl}^{-} (g) + aq \to {Cl}^{-} (ag) ΔH = - 364 kJ \end{array}$

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