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The LCM of $x^{2} - 10 x + 24, x^{2} - 8 x + 12$ and $x^{2} - 6 x + 8$ is $k (x - 2) (x - 4) (x - 6)$ , then $k$ is

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Detailed Solution

$x^{2} - 10 x + 24 = (x - 6) (x - 4)$

$x^{2} - 8 x + 12 = (x - 6) (x - 2)$

$x^{2} - 6 x + 8 = (x - 2) (x - 4)$

LCM is $(x - 2) (x - 4) (x - 6)$

$K (x - 2) (x - 4) (x - 6) = (x - 2) (x - 4) (x - 6)$

$K = 1$

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