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Q.

The L.C.M of $x^{3} - 1$ and $x^{2} + x + 1$ is

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a

$x - 1$

b

$x^{2} + x + 1$

c

$(x^{3} - 1) (x^{2} + x + 1)$

d

$x^{3} - 1$

answer is C.

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Detailed Solution

$x^{3} - 1 = (x - 1) (x^{2} + x + 1)$

and $(x^{2} + x + 1)$

∴ $L . C . M$ $= (x - 1) (x^{2} + x + 1)$

$= x^{3} - 1$

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