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Q.

The least count of a stop watch is (1/5) s. The time of 20 oscillations of a pendulum is measured to be 25 s. The maximum percentage error in this measurement is

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a

0.8 %

b

8 %

c

1 %

d

16 %

answer is C.

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Detailed Solution

$ΔT = \frac{1 / 5}{20} and T = \frac{25}{20}; % error = \frac{ΔT}{T} \times 100 % = 0.8 %$

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