The least number which when divided by 2, 3, 4, 5 and 6 leaves the remainder 1 in each case. If

the same number is divided by 7 it leaves no remainder. The number is?

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answer is B.

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Detailed Solution

Concept: If the least common multiple number is found, the least common multiple with a remainder of 0 is obtained. Therefore, (least common multiple + 1) is found because the remainder 1 remains.
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The remaining required number remains 1 if divisible by 2, 3, 4, 5
If 6 is divisible by 7, there is not much. Therefore, the required number is in the form of

is a multiple of 7
Let's check

is divisible by 7
By replacing natural numbers in order
Question Image

The minimum number 301, When divided by 2, 3, 4, 5 and 6 leaves the remainder 1, But if you divide by 7, There is no rest.
Hence, the correct answer is option 2) 7

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