The least number which when divided by 6, 15 and 18 leave remainder 5 is ____.

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Detailed Solution

The least number which when divided by 6, 15 and 18 leave remainder 5 is 95.
Here, we have to find the least number which when divided by 6, 15 and 18 leave remainder 5.
Prime factorization of 6, 15, 18 is,
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LCM = 2 × 3 × 3 × 5 = 90.
Add 5 to the LCM.
The required number is 90 + 5 = 95.
Therefore, the least number which when divided by 6, 15 and 18 leave remainder 5 in each case is 95.

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