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Q.

The least resolvable angle by a telescope using objective of aperture 5m is nearly ( $λ = 4000 \overset{o}{A}$ )

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a

$\frac{1}{50} minute$

b

$\frac{1}{50^{\circ}}$

c

$\frac{1}{500} \sec$

d

$\frac{1}{50} \sec$

answer is C.

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Detailed Solution

$θ = \frac{1 .22 λ}{a}$

$= \frac{1.22 \times 4000 \times 10^{- 10}}{5} \times \frac{180}{π} \times 3600 \sec$

$= \frac{1}{50} \sec$

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