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Q.

The least value of $g (t) = 8 t - t^{4} on [- 2, 1]$ is

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a

-16

b

-20

c

-32

d

7

answer is C.

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Detailed Solution

$g^{'} (t) = 0 \Rightarrow 8 - 4 t^{3} = 0 \Rightarrow t^{3} = 2 so t = 2^{1 / 3}$

but $2^{1 / 3} \notin [- 2, 1]$ , Now $g (- 2) = - 32, g (1) = 7$

So –32 in the least value.

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