The length and breadth of a rectangular cardboard are 65 cm and 50 cm respectively. If the length of the side of a square-shaped cardboard is 5 cm, then how many such square cardboards can be placed on the rectangular cardboard such that there is no overlapping of the square cardboards?

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100

120

110

130

answer is D.

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Detailed Solution

The given information can be represented by a figure as:

Question Image

Number of square cardboards that can be placed along the length of the rectangular cardboard = $\frac{65 cm}{5 cm} = 13$

Number of square cardboards that can be placed along the breadth of the rectangular cardboard = $\frac{50 cm}{5 cm} = 10$

∴ Number of square cardboards that can be placed over the rectangular cardboard = 13 × 10 = 130

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