The length and breadth of a rectangular sheet are 16.2 cm and 10.1 cm, respectively. The area of the sheet in appropriate significant figures and error is 

Given, length, l=(16.2± 0.1)cm
Breadth, b= (10.1± 0.1)cm
Area, A= lx b =(16.2 cm)x (10.1 cm)= 163.62 cm²
Rounding off to three significant digits, area, A = 164 cm²

$\because \frac{\Delta A}{A}=\frac{\Delta l}{l}+\frac{\Delta b}{b}=\frac{0.1}{16.2}+\frac{0.1}{10.1}=\frac{1.01+1.62}{16.2\times 10.1}=\frac{2.63}{163.62}$

$\Rightarrow \Delta A=A\times \frac{2.63}{163.62}=163.62\times \frac{2.63}{163.62}$

= 2.63 cm²

$∆$A = 3 $c{m}^2$ (By rounding off to one significant figure)

$\therefore$ Area,  $A= A \pm ∆A = (164 \pm 3) c{m}^2$