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The length and width of a swimming pool are $50 m$ and $15 m$ , respectively. If the depth of the swimming pool at one end is $10 m$ and at the other end is $20 m$ , then what will be the volume of water in the swimming pool?

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12150 m 3

11250 m 3

11520 m 3

10052 m 3

answer is B.

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Detailed Solution

Given- length of a swimming pool = 50 m.
Width of a swimming pool = 15 m.
Depth of a swimming pool at one end = 10 m.
Depth of a swimming pool at other end = 20 m.
Volume of trapezium based prism= area of trapezium

\times

width of swimming pool
Question Image

Capacity of the pool = volume of the trapezium based prism ABCDEFGHA

= area of trapezium ABCD (C E) = 12 (B C + A D) (C D) (C E) = 12 (10 + 20) 50 15 = 11250 m 3

Thus, the volume of water in the swimming pool is

11250 m 3

.
Hence, option 2 is the correct option.

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