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Q.

The length of a hall is 20m and width 16m. The sum of the areas of the floor and the flat roof is equal to the sum of the area of the four walls. ____ is the height of the hall.

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Detailed Solution

Let x be the size of the hall's floor
x = l × b=20 × 16 = 320

m^{2}

The total size of the hall's four walls, which will be a sum because the room is rectangular in shape
Area = (l × h + b × h + l × h + b × h)
Area =2l × h + 2b × h
Area =2h(l + b)
Now, it is said that the sum of the flat roof and floor's areas, where the floor's area is equal to the roof's area and the sum of the four walls' areas
2x=2h(l+b)
x=h(l+b)
320=h(20+16)
320=36h
h=

\frac{320}{36}

=8.89m

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