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Q.

The length of a rod is 20 cm and area of cross-section 2 cm2 . The Young’s modulus of the material of wire is 1.4 x 1011N / m2 . If the rod is compressed by 5 kg-wt along its length, then increase in the energy of the rod in joules will be

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a

22.5 x 10-4

b

8.57 x 10-6

c

45.0 x 10-5

d

9.8 x 10-5

answer is A.

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Detailed Solution

Energy 
=12Fl=12×F×FLAY=12×F2LAY  =12×(50)2×20×10−22×10−4×1.4×1011=8.57×10−6J

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