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The length of a seconds hand in watch is $1 c m$ . The change in velocity of its tip in $15 s$ is

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$\frac{π \sqrt{2}}{30} c m / s$

$\frac{π}{30 \sqrt{2}} c m / s$

$\frac{π}{30} c m / s$

Zero

answer is D.

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In 15 s, velocity vector (of same magnitude) will rotate $90^{o}$

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