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The length of each rail is 10m. The coefficient linear expansion of steel is 12×10^–6/°C and range of variation of temperature at the given place is 15°C. The gap to be left between the rails is

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0.00022 m

0.0018 m

0.05 m

0.0012 m

answer is A.

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Detailed Solution

$\begin{array}{l} α = 12 \times 10^{- 6}, ℓ = 10 m, Δt = 15^{\circ} C \\ Δ ℓ = α ℓ Δt = 12 \times 10^{- 6} \times 10 \times 15 = 0.00180 \end{array}$

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