The length of magnet of moment $5 {Am}^{2}$ is 14cm. The magnetic induction at a point, equidistant from both the poles is $3.2 \times 10^{- 5}$ T. The distance of point from each pole is

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25cm

5cm

15cm

10cm

answer is A.

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Detailed Solution

This is NOT a short dipole.

$B_{Net} = 2 B \cos θ = 2 \times \frac{μ_{0} m}{4 π x^{2}} \times \frac{\frac{l}{2}}{x} = \frac{μ_{0}}{4 π} \times \frac{M}{x^{3}}$

where $x$ is equidistance from each pole.

$3.2 \times 10^{- 5} = 10^{- 7} \times \frac{5}{x^{3}}$

$\Rightarrow x = \frac{1}{4} m = 25 cm$

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