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The length of minutes hand in a pendulum clock is 10 cm. The speed of the tip of the hand is

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$\frac{π}{6000} {ms}^{- 1}$

$\frac{π}{18000} {ms}^{- 1}$

$\frac{π}{3600} {ms}^{- 1}$

$\frac{π}{1200} {ms}^{- 1}$

answer is B.

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Detailed Solution

T = 1 hr = 3600 sec
$\begin{array}{l} w = \frac{2 π}{T} = \frac{π}{1800} rad / \sec \\ ∴ v = rw = 0.1 \times \frac{π}{1800} \\ = \frac{π}{18000} m / s \end{array}$

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