The length of perpendicular from the origin to the plane which makes intercepts 13,14,15 respectively on the coordinate axes is

xa+yb+zc=13x+4y+5z-1=0|-1|9+16+25=150=152

The length of perpendicular from the origin to the plane which makes intercepts 13,14,15 respectively on the coordinate axes is

xa+yb+zc=13x+4y+5z-1=0|-1|9+16+25=150=152

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The length of perpendicular from the origin to the plane which makes intercepts $\frac{1}{3}, \frac{1}{4}, \frac{1}{5}$ respectively on the coordinate axes is

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$\frac{1}{5 \sqrt{2}}$

$\frac{1}{10}$

$5 \sqrt{2}$

answer is A.

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$\begin{array}{rcl} \frac{x}{a} + \frac{y}{b} + \frac{z}{c} & = & 1 \\ 3 x + 4 y + 5 z - 1 & = & 0 \\ \frac{| - 1 |}{\sqrt{9 + 16 + 25}} & = & \frac{1}{\sqrt{50}} = \frac{1}{5 \sqrt{2}} \end{array}$

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The length of perpendicular from the origin to the plane which makes intercepts 13,14,15 respectively on the coordinate axes is

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The length of perpendicular from the origin to the plane which makes intercepts $\frac{1}{3}, \frac{1}{4}, \frac{1}{5}$ respectively on the coordinate axes is