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Q.

The length of second's hand in watch is 1 cm. The change in velocity of its tip in 15 seconds is

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a

zero

b

$\frac{π}{30} cm / s$

c

$\frac{π \sqrt{2}}{30} cm / s$

d

$\frac{π}{30 \sqrt{2}} cm / s$

answer is D.

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Detailed Solution

$Δv = 2 vsin (\frac{90^{0}}{2}) = 2 vsin 45^{0} = 2 v \times \frac{1}{\sqrt{2}} = \sqrt{2} v$

$= \sqrt{2} \times rω = \sqrt{2} \times 1 \times \frac{2 π}{60} = \frac{\sqrt{2} π}{30} cm / s$

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