The length of the common chord of the two circles (x–a)2+(y–b)2 = c2, (x–b)2+(y–a)2 = c2 is

A common chord is x – y = 0 length of the chord =2r2−d2=2C2−a−b22=4c2−2(a−b)2

The length of the common chord of the two circles (x–a)2+(y–b)2 = c2, (x–b)2+(y–a)2 = c2 is

A common chord is x – y = 0 length of the chord =2r2−d2=2C2−a−b22=4c2−2(a−b)2

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The length of the common chord of the two circles (x–a)²+(y–b)²= c², (x–b)²+(y–a)²= c² is

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$\sqrt{4 c^{2} + 2 (a + b)^{2}}$

$\sqrt{4 c^{2} + 2 (a - b)^{2}}$

$\sqrt{c^{2} - (a - b)^{2}}$

$\sqrt{4 c^{2} - 2 (a - b)^{2}}$

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A common chord is x – y = 0 length of the chord $= 2 \sqrt{r^{2} - d^{2}}$
$= 2 \sqrt{C^{2} - {(\frac{a - b}{\sqrt{2}})}^{2}} = \sqrt{4 c^{2} - 2 (a - b)^{2}}$

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The length of the common chord of the two circles (x–a)2+(y–b)2 = c2, (x–b)2+(y–a)2 = c2 is

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The length of the common chord of the two circles (x–a)²+(y–b)²= c², (x–b)²+(y–a)²= c² is