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The length of the double ordinate of the parabola $y^{2} - 8 x + 6 y + 1 = 0$ which is at a distance of 32 units from vertex is

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answer is C.

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Detailed Solution

$4 a = \frac{|- 8|}{1} \Rightarrow a = 2, p = 32$

Distance is AB $= \sqrt{4 a p} = 4 \sqrt{2 (32)}$

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