The length of the parallel sides of a trapezium is $14$cm and $6$cm and the height is $5$cm. Find its area.

Given that, the length of one side of the trapezium $b_1$ = 6cm and another is $b_2$ =14cm.
The height of the trapezium h = 5cm.
Drawing the figure from the given data.

We have to find the area of the trapezium.
The area of trapezium, is A$=\frac{1}{2}\left(b_1+b_2\right)\times h$.
Substitute the values,
A $=\frac{1}{2}\times (14+6)\times 5$ 

$=\frac{1}{2}\times 20\times 5$ 

$=50 {\mathrm{cm}}^2 \mathrm{or} 0.005{\mathrm{m}}^2$.